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This characteristic of the Pearson correlation was known to the ancients. 22 SSE can never be A larger than SST. B smaller than SST. C equal to 1. D equal to zero. View Answer Answer: larger than SST 23 If two variables, x and y, have a In fact, if SSE = 0, then SST = SSR, which means all the observations lie on the regression line - i.e., a perfect fit. As SSE gets larger, SSR gets smaller indicating a poorer fit between the observations and the regression line. In our example problem: SST = 8; SSR = 7.2; and SSE = 0.8. Therefore: SST = SSR + SSE or 8 = 7.2 + 0.8 5 a.
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There's not room left for SST to be greater than SSE + SSR. (3) The problem with your illustration You can't look at SSE and SSR in a pointwise fashion. For a particular point, the residual may be large, so that there is more error than explanatory power from X.
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The coefficient of determination represents the ratio of SSR to SST. regression sum of squares (SSR) can never be greater than the total sum of squares (SST).
SSE can never be a. larger than SST b. smaller than SST c. equal to 1 d. equal to zero. a.
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SSE can never be * a.smaller than SST b.largest than SST c.equal to zero d.equal to 1 1 See answer pranav354235 is waiting for your help.
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SSE can never be * a.smaller than SST b.largest than SST c.equal to zero d.equal to 1 1 See answer pranav354235 is waiting for your help. Add your answer and earn points.
R 2 = 1 - SSE / SST. the R-squared will be larger than if they are close together. This characteristic of the Pearson correlation was known to the ancients. 22 SSE can never be A larger than SST. B smaller than SST. C equal to 1.
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1 Sep 2004 unbiased estimator has a variance which is larger that the variance of by If SSE and SSR are independent, then SST will be distributed as a P
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